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5x^2+3x-1800=0
a = 5; b = 3; c = -1800;
Δ = b2-4ac
Δ = 32-4·5·(-1800)
Δ = 36009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36009}=\sqrt{9*4001}=\sqrt{9}*\sqrt{4001}=3\sqrt{4001}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{4001}}{2*5}=\frac{-3-3\sqrt{4001}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{4001}}{2*5}=\frac{-3+3\sqrt{4001}}{10} $
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